![]() The net force on the ball is acting toward the centre of the horizontal circle. The tree is 4.9 m tall as shown below.Īssume the acceleration due to gravity is g = 9.8 \ ms^ Calculate the force exerted on the object by the surface.Ī golfer hits a hole-in-one by just clearing a tree situated in front of them. (a)ĭerive an expression for the magnitude of the gravitational acceleration on the surface of Planet Z in terms of the gravitational acceleration on the surface of the Earth, g.Ī 10 kg object rests on a horizontal plane at the surface of Planet Z. Planet Z has twice the mass and twice the radius of the Earth. Calculating energy changes that occur when satellites move between orbits.ġ0 Must Know Questions for HSC Physics Module 5 Question 1 (4 marks).Calculating the total energy of a planet or satellite in its orbit.Analysing quantitatively the orbital motion of planets and artificial satellites using Kepler’s Laws.Calculating the gravitational acceleration of objects.Analysing quantitatively and qualitatively the non-uniform circular motion of objects. ![]() Analysing uniform circular motion involving:.Analysing the motion of projectiles in a variety of situations.What are commonly asked exam question types in HSC Physics Module 5?ħ commonly asked question types from the HSC Physics Module 5 Advanced Mechanics syllabus are listed below: NESA Content Block 10 Must Know Questions to ace your next HSC Physics Module 5 Exam.7 commonly asked question types from HSC Physics Module 5.The key to acing HSC Physics Module 5 begins with having a solid understanding of all the Physics concepts in Module 2. The concepts covered in HSC Physics Module 5 Advanced Mechanics are an extension of the foundational concepts taught in Year 11 Physics Module 2 Dynamics. The energy transformations that take place within and around the system.The analysis of forces acting on a system, and.HSC Physics Module 5 demands students demonstrate a high level of competency in their skills, knowledge and understanding of: This alarm shall signal when the power supply drops below 24 VDC.Test your exam readiness for HSC Physics Module 5 ![]() And to add a voltage monitoring alarm to the power supply which is used to power the 4-20 mA current loop system. We recommend to perform a loop test according the Namur NE43 current loop range of 3,4-21,5 mA on every loop during commissioning. Hence, alarms may not sound as the trip level is not reached due to the insufficient voltage supply to the current loop. Due to the insufficient voltage supply this value is not correct which may cause serious problems in the operation of the plant in which this situation occurs. The PLC, DCS system or other receiver will not detect the insufficient voltage supply, so the measured current will be used as a normal measured value. When the power supply voltage to the current loop is to low, the required maximum current of 20 mA can not flow.The calculation shows the current will stick at a certain level. $$ U_) $$Ĭurrent loop voltage calculator conclusion The current loop voltage calculation is based on the following formula: When power supply is sufficient this is the current set by the Loop Tester, if supply is insufficient the current is calculated from Ohm's law. The Current is the current flowing through the loop. The voltage drop is depending on the current flowing through the cable. This resistance will cause a voltage drop as indicated in the calculator. Depending on the length and cross section of the cable, the cable has a resistance. The cable connects the Loop tester/measurement transmitter to the power supply and receiver. When the voltage drops below the minimum required voltage the current in the loop will also drop which will cause measurement errors. The loop tester needs sufficient voltage to operate. ![]() ![]() The Loop tester can be replaced by a process instrument / measurement transmitter such as a pressure or temperature transmitter. The current loop tester will set the current in the loop. A fixed voltage, the internal electronics will convert the current from the loop to a (digital) signal. A fixed resistor, the resistor will convert the current in the loop to a variable voltage which is evaluated by the receiver.Ģ. Receivers typically have 2 types of inputs which can be selected in the current loop voltage simulation.ġ. The receiver is a PLC, DCS system or some other device such as a I/P converter display etc. Typical power supply for industrial systems is 24VDC. The power supply provides the power to the current loop. V The current loop voltage diagram consist of the following items: Power Supply ![]()
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